(2sqrt(5)+3sqrt(2))^(2)

(sqrt(5)-sqrt(2))(sqrt(2)-sqrt(3)) (sqrt(5)-sqrt(3))^(2)

(sqrt(5)-sqrt(2))(sqrt(2)-sqrt(3)) (sqrt(5)-sqrt(3))^(2)

(sqrt(5)-sqrt(2))(sqrt(2)-sqrt(3)) (sqrt(5)-sqrt(3))^(2)

Simplify (i) (4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5)) (ii) (1)/(sqrt(3) + sqrt(2)) - (2)/(sqrt(5)-sqrt(3)) -(2)/(sqrt(2) - sqrt(5)) (iii) (2+sqrt(3))/(2-sqrt(3)) + (2-sqrt(3))/(2+sqrt(3)) + (sqrt(3)-1)/(sqrt(3)+1) (iv) (2+sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3)) -(8sqrt(3))/(sqrt(6)+sqrt(2))

(1)/(2sqrt(5)-sqrt(3))-(2sqrt(5)+sqrt(3))/(2sqrt(5)+sqrt(3)) =

Rationalise the denominator (2sqrt(3)-sqrt(5))/(2sqrt(2)+3sqrt(3))

The radius of the circle passing through the points (1, 2), (5, 2) and (5, -2) is : (A) 5sqrt(2) (B) 2sqrt(5) (C) 3sqrt(2) (D) 2sqrt(2)