`(tan theta+sectheta-1)/(tantheta - sec theta +1)=(1+sintheta)/(costheta)`

prove (tantheta +sectheta-1)/(tantheta-sectheta+1) = (1+sintheta)/(costheta)

Prove the following identities: (tantheta+sectheta-1)/(tantheta-sectheta+1)=(1+sintheta)/(costheta)

Prove that (tantheta +sectheta -1)/(tantheta-sectheta+1)=(1+sintheta)/costheta

Prove the following (tantheta+sectheta-1) /(tantheta-sectheta+1) =(1+sintheta) /costheta

Prove that (tantheta+Sectheta+1)/(-tantheta+Sectheta+1)=(Costheta)/(1-Sintheta)

Prove that : (sectheta+tantheta-1)/(tantheta-sectheta+1)=(costheta)/(1-sintheta)

Pove that- sectheta-tantheta=1/(sectheta+tantheta)=(1-sintheta)/costheta

Prove that: (tantheta)/(sectheta -1) = (tan theta + sec theta + 1)/(tan theta + sec theta -1)

Prove that- (sectheta+tantheta)/(sec-tantheta)=((1+sintheta)/costheta)^2

If theta epsilon (0, pi/2) then the value of |((sintheta+cosectheta)^2, (sintheta- cosectheta)^2,1 ),((costheta+sectheta)^2, (costheta-sectheta)^2, 1),((tantheta+cottheta)^2, (tantheta-cottheta)^2, 1)|= (A) sintheta+costhetas+tantheta (B) 1 (C) 0 (D) 4