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If z=(lambda+3)+isqrt(5-lambda^2) then t...

If `z=(lambda+3)+isqrt(5-lambda^2)` then the locus of Z is

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`z = (lambda+3) +isqrt(5-lambda^2)`
`=>x+iy = (lambda+3) +isqrt(5-lambda^2)`
`=> x = lambda+3=> lambda = x-3`
`=>lambda^2 = (x-3)^2->(1)`
`=>y = sqrt(5-lambda^2) => y^2 = (5-lambda^2)`
`=>lambda^2 = 5-y^2->(2)`
From (1) and (2),
`=> (x-3)^2 = 5-y^2`
...
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