[(x+3)/(2)-y=2;(x-3)/(2)+2y=4(1)/(2)" then "x=],[01],[014/3],[051/2],[024/5]

(3) 3x-2y=(5)/(2) (1)/(3)x+3y=-(4)/(3)

3x-2y=(5)/(2),(1)/(3)x+3y=(-4)/(3)

If _(i-1)(x_(i)^(2)+y_(i)^(2))<=2x_(1)x_(3)+2x_(2)x_(4)+2y_(2)y_(3)+2y_(1)y_(4)sum_(i-1)^(4)(x_(i)^(2)+y_(i)^(2))<=2x_(1)x_(3)+2x_(2)x_(4)+2y_(2)y_(3)+2y_(1)y_(4) the points (x_(1),y_(1)),(x_(2),y_(2)),(x_(3),y_(3)),(x_(4),y_(4)) are the vertices of a rectangle collinear the vertices of a trapezium none of these

If (2x + y + 2)/(5) = ( 3x - y + 1)/( 3 ) = ( 2 x + 2y + 1 )/(6) then

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

If ((x_(1),x_(2)),((y_(1),y_(2))-((2,3),(0,1)),=((3,5),(1,2)) then find x_(1),x_(2),y_(1),y_(2) ,

Evaluate : (x^(1//3)+y^(1//3))(x^(2//3)-x^(1//3)y^(1//3)+y^(2//3)) , when x=4(5)/(7) " and " y=5(2)/(7) .

The solution of the differential equation xdy/dx+2y=x^(2),(xne0) with y(1)=1, is (a) y=x^(2)/4+3/(4x^(2)) (b) y=x^(3)/5+1/(5x^(2)) (c) y=3/4x^(2)+3/(4x^(2)) (d) y=4/5x^(3)+1/(5x^(2))

If [{:(x_(1),x_(2)),(y_(1),y_(2)):}]-[{:(2,3),(0,1):}]=[{:(3,5),(1,2):}] determine x_(1),x_(2),y_(1),y_(2) .