sin theta=sqrt(3)/2

Find the general values of theta from the following equations: i) sin3theta=sqrt(3)/2 , ii) cos4theta=1/sqrt(2) iii) tan2theta=sqrt(3) iv) "cosec"3theta=2

Find the general values of theta from the following equations: i) sin3theta=sqrt(3)/2 , ii) cos4theta=1/sqrt(2) iii) tan2theta=sqrt(3) iv) "cosec"3theta=2

Find the general solution of sin theta=- sqrt3/2

If sin theta=sqrt3/2 then prove that 4cos^3 theta-3cos theta=-1

If sin theta=sqrt3/2 and cos theta= -1/2 then theta lies in :

Q.1. (B) solve the following: If sin theta = sqrt3/2 / then find theta ,

If r cos theta = 1/2 and r sin theta = sqrt3/2 , then find the value of r , when 0 ∘ <θ<90 ∘ .

If r sin theta=sqrt(3),r+4sin theta=2(sqrt(3)+1), and 0<=theta<=2 pi, then theta=

If r sin theta = sqrt(3), r + 4 sin theta = 2(sqrt(3)+1), 0 le theta le 2pi , then theta =

The number of values of theta in[0,2 pi] satisfying r sin theta=sqrt(3) and r+4sin theta=2(sqrt(3)+1) is