(y-8)and(3y-4)

Solve: (y-8)/3=(7-4y)/7

Solve: (y-8)/3=(7-4y)/7

3(y+8)=10(y-4)+8

Point (0, beta) lies on or inside the triangle fromed by the lines y=0, x+y=8 and 3x - 4y + 12 =0 . Then beta can be :

Point (0, beta) lies on or inside the triangle fromed by the lines y=0, x+y=8 and 3x - 4y + 12 =0 . Then beta can be :

Express the following equation in matrix form and solve them by the method of reduction: 2x-y+z = 1 , x+2y+3z = 8 and 3x+y-4z = 1

Find the equation of the straight line which passes through the point (2, -9) and the intersection of the lines 2x+5y-8=0 and 3x-4y=35