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[(i,0,1),(-1,i,0),(-i,2,1)]+[(2,i,0),(0,...

`[(i,0,1),(-1,i,0),(-i,2,1)]+[(2,i,0),(0,2,1),(1,0,-1)]=`

A

`[(i+2,i,1),(-i,i+2,1),(-i+1,2,0)]`

B

`[(i+2,i,1),(-1,i+2,1),(i+1,2,0)]`

C

`[(i-2,i,1),(1,i+2,1),(-i+1,2,0)]`

D

`[(i+2,i,1),(-1,i+2,1),(i-1,2,0)]`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Adj[(1,0,2),(-1,1,-2),(0,2,1)]=[(5,a,-2),(1,1,0),(-2,-2,b)]implies[(a,b)]=

    A
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    B
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    C
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    D
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  • If A=[(1,2,3),(2,0,-1),(0,2,-2)],B=[(1,0,0),(0,-1,0),(-1,0,2)] then 4A-3B=

    A
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    B
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    D
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  • Match the following from List - I to List - II {:(,"List - I",,"List - II"),(I.,[(1,1),(1,0)],(a),0),(II.,[(1,1),(1,1)],(b),1),(III.,[(0,0),(0,0)],(c),2),(IV.,[(1,0,0),(0,1,0),(0,0,1)],(d),3):}

    A
    a,b,c,d
    B
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    C
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    D
    c,b,a,d

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