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Adj[(1,0,2),(-1,1,-2),(0,2,1)]=[(5,a,-2)...

`Adj[(1,0,2),(-1,1,-2),(0,2,1)]=[(5,a,-2),(1,1,0),(-2,-2,b)]implies[(a,b)]=`

A

`[(-4,1)]`

B

`[(-4,-1)]`

C

`[(4,1)]`

D

`[(4,-1)]`

Text Solution

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The correct Answer is:
C
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DIPTI PUBLICATION ( AP EAMET)-MATRICES-EXERCISE 1C MCQ (INVERSE MATRIX)
  1. If A=[(-1,-2,-2),(2,1,-2),(2,-2,1)] then adjA=

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  2. If A=[(-1,-2,-2),(2,1,-2),(2,-2,1)], then A^(T)

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  3. Adj[(1,0,2),(-1,1,-2),(0,2,1)]=[(5,a,-2),(1,1,0),(-2,-2,b)]implies[(a,...

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  4. The inverse of the matrix [(0,0,1),(0,1,0),(1,0,0)] is

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  5. The inverse of [(0,1,0),(1,0,0),(0,0,1)] is

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  6. The matrix having the same matrix as its inverse is

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  7. The inverse of [(3,5,7),(2,-3,1),(1,1,2)] is

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  8. The inverse of [(1,3,3),(1,4,3),(1,3,4)] is

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  9. The inverse of [(1,2,-3),(0,1,2),(0,0,1)] is

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  10. The inverse of the matrix [(7,-3,3),(-1,1,0),(-1,0,-1)] is

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  11. The inverse of [(cos theta, -sin theta, 0),(sin theta, cos theta, 0),(...

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  12. If A=[(1,0,2),(2,1,0),(3,2,1)] then 3A^(-1)=

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  13. If A=[(1,2,2),(2,1,-2),(-2,2,-1)] thenA^(T)=

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  14. IF A=[{:(3,-3,4),(2,-3,4),(0,-1,1):}] then show that A^-1=A^3.

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  15. A=((1,0,1),(0,1,1),(0,1,0))impliesA^(2)-2A=

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  16. If A=[(cosx, sin x, 0),(-sin x, cosx, 0),(0,0,1)]=f(x) then A^(T)=

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  17. A(alpha, beta)=((cos alpha, sin alpha, 0),(- sin alpha, cos alpha, 0),...

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  18. If F(x)=[(cosx,-sinx,0),(sinx,cosx,0),(0,0,1)] and G(x)=[(cosx,0,sinx)...

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  19. If |(1,-1,x),(1,x,1),(x,-1,1)| has no inverse, then the real value of ...

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  20. If A=[(1,4,2),(2,-1,4),(-3,7,-6)] then A has

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