Home
Class 12
MATHS
Let vector of magnitude 3 sqrt(6) along ...

Let vector of magnitude `3 sqrt(6)` along the internal bisector of the angle between the vectors 4i - 7j + 4k and i + 2j - 2k is

A

`+- (7i + 2j + 2k)`

B

`+- (7i - j + 2k)`

C

`+- (7i - j - 2k)`

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ADDITION OF VECTORS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 1|10 Videos

  • ADDITION OF VECTORS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 2|4 Videos

  • ADDITION OF VECTORS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 4|8 Videos

  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET-4 (SPECIAL TYPE QUESTIONS)|15 Videos

Similar Questions

Explore conceptually related problems

The angle between the vectors (i + j + k) and (i- j - k) is

The vector of magnitude 3sqrt(6) along the bisector of the angle between the vectors 4bar(i)-7bar(j)+4bar(k) and bar(i)+2bar(j)-2bar(k) is

The sine of the angle between the vectors I + 3j - 2k, 2i - 4j - k is

If theta is th angle between the vector 2i - 2j + 4k and 3i + j + 2k, then sin theta =

The vector ai + bj + ck is a bisector of the angle between the vectors i + j and j + k if

The distance between the points i + 6j + 7k, -3i + 4j + 3k is

The unit vector perpendicular to each of the vectors 2i - j + k and 3i + 4j - k is

The angle between the planes r. (2i - j + 2k) = 3 and r. (3i - 6j + 2k) = 4

Find the angle between two vectors vec(A)=2i+j-k and vec(B)=i-k .

The cross product of the vectors (2i - 3j + 4k) and (I + 4j -5k) is