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A: The equation to the locus of poin...

A: The equation to the locus of points which are equidistant from the points ` ( - 3, 2 ) , (0, 4 )` is ` 6x + 4y - 3 =0 ` .
R : The locus of points which are equidistant to ` A, B ` is perpendicular bisector of AB

A

A true, R true and R is correct explanation of A

B

A true, R true but R is not the correct explantion of A

C

A is true but R is false

D

A is false but R is true

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Equation to the locus of points which are equal distance from the points (1, -3, 4), (1, 3, 4) is

    A
    xy = 0
    B
    y = 0
    C
    z = 0
    D
    x = 0

  • The equation to the locus of points which are equal distance from the points (1,-3,4),(1,3,4) is

    A
    xy=0
    B
    y=0
    C
    z=0
    D
    x=0

  • The equation to the locus of points equidistant from the points (-3, 4),(3, 4) is

    A
    x=1
    B
    x=2
    C
    x=3
    D
    x=0

    • Similar Questions

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    Find the equation to the locus of points equidistant from the points (-3,2),(0,4)

    Find the equation of locus of a point which is equidistant from the coordinate axes.

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    The locus of point which is equidistant from the points (-2,2,3),(3,4,5) is

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