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underset(x to 0)"Lt" sqrtx=...

`underset(x to 0)"Lt" sqrtx=`

A

0

B

`sqrt2`

C

`sqrt3`

D

does not exist

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • underset(x to 0)"Lt" (sqrt(1+x+x^2))/(x)=

    A
    0
    B
    1
    C
    2
    D
    `1//2`

  • underset(x to 0+)"Lt" cot x=

    A
    0
    B
    `oo`
    C
    `-oo`
    D
    does not exist

  • underset(x to 0-)"Lt" cot x=

    A
    0
    B
    `oo`
    C
    `-oo`
    D
    does not exist

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