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Slope of the normal to the curve x^3+y^3...

Slope of the normal to the curve `x^3+y^3=6xy` at `(3,3)` is

A

0

B

1

C

-1

D

`1//sqrt(2)`

Text Solution

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The correct Answer is:
B
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DIPTI PUBLICATION ( AP EAMET)-APPLICATIONS OF DIFFERENTIATION-EXERCISE 1B (TANGENT AND NORMAL)
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