Home
Class 12
MATHS
The point on the curve y=x^2+5, the tang...

The point on the curve `y=x^2+5`, the tangent at which is perpendicular to the line `x+2y=2` is

A

`(1,6)`

B

`(1,-6)`

C

`(-1,6)`

D

`(-1,-6)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1C (RATE OF CHANGE)|78 Videos

  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1D (MEAN VALUE THEOREMS)|28 Videos

  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1A (APPROXIMATIONS AND ERRORS)|67 Videos

  • ADDITION OF VECTORS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 4|8 Videos

  • BINOMIAL THEOREM

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) SET - 4|4 Videos

Similar Questions

Explore conceptually related problems

The point on the curve y=x^3+x-2 , the tangent at which is parallel to the line y=4x-1 is

The point on the curve y=x^3+5 , the tangent at which is parallel to the line 12x - y = 7 is

The points on the curve 2a^2y=-x^3-3ax^2 at which the tangent is perpendicular to y-axis is

The points on the curve y=x^2+sqrt(1-x^2) at which the tangent is perpendicular to x-axis are

Find the points on the curve at which the tangents to the curve. y=x^(2)+5 are perpendicular to x+2y=2

The line y=6x+1 touches the parabola y^(2)=24x . The coordinates of a point P on this line, from which the tangent to y^(2) =24x is perpendicular to the line y=6x+1. is

The equation of the tangent to the curve y=x^3+3x^2-5 and which is perpendicular to 2x-6y+1=0 is

Find the equation of the tangent to the curve. y=x^(3)+3x^(2)-5 and which is perpendicular to 2x-6y+1=0

The point on the curve x^2+y^2-2x-3=0 at which the tangent is parallel to x-axis is

DIPTI PUBLICATION ( AP EAMET)-APPLICATIONS OF DIFFERENTIATION-EXERCISE 1B (TANGENT AND NORMAL)
  1. The coordinates of the point P on the curve x=a(theta+sintheta),y=a(1-...

    Text Solution

    |

  2. Points at which the tangents to the hyperbola y=(x-1)/(x+1) are parlle...

    Text Solution

    |

  3. The point on the curve y=x^2+5, the tangent at which is perpendicular ...

    Text Solution

    |

  4. The curvey-e^(xy)+x=0 has a vertical tangent at the point

    Text Solution

    |

  5. The point on the curve y=x^3+x-2, the tangent at which is parallel to ...

    Text Solution

    |

  6. The line x//a+y//b=1 is a tangent to curve y=be^(-x//a) at the point

    Text Solution

    |

  7. The points on the curve y=x^3, the tangent at which are inclined at an...

    Text Solution

    |

  8. The point on the curve x^2+y^2-2x-3=0 at which the tangent is parallel...

    Text Solution

    |

  9. The point on the curve x^4-4x^3+4x^2+1 at which the tangent is paralle...

    Text Solution

    |

  10. The points on the curve y=x^2+sqrt(1-x^2) at which the tangent is perp...

    Text Solution

    |

  11. The points on the curve 2a^2y=-x^3-3ax^2 at which the tangent is perpe...

    Text Solution

    |

  12. The equation of the tangent to the curve 4x^2+9y^2=40 and having slope...

    Text Solution

    |

  13. The equation of the tangent to the curve 9x^2+16y^2=52 and which is pa...

    Text Solution

    |

  14. The equation of the tangent to the curve x^2+y^2=52 and which is paral...

    Text Solution

    |

  15. The equation of the tangent to the curve y=x+4/x^2, that is parallel t...

    Text Solution

    |

  16. The equation of the tangent to the curve y=x^3+3x^2-5 and which is per...

    Text Solution

    |

  17. The equation of the tangent to the curve y^2=4x+5 and which is paralle...

    Text Solution

    |

  18. The equation of the tangent to the curve x^2+2y=8 and which is perpend...

    Text Solution

    |

  19. The points of contact of the tangents drawn from origin to the curve 3...

    Text Solution

    |

  20. The point of contact of the tangents drawn from origin to the curve y=...

    Text Solution

    |