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The equation of the normal to the curve ...

The equation of the normal to the curve `y=be^(-x//a)` where it cuts y-axis is

A

`x/a+y/b=1`

B

`x/a-y/b=1`

C

`ax+by-b^2=0`

D

`ax-by+b^2=0`

Text Solution

Verified by Experts

The correct Answer is:
D
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DIPTI PUBLICATION ( AP EAMET)-APPLICATIONS OF DIFFERENTIATION-EXERCISE 1B (TANGENT AND NORMAL)
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  6. The normal to he curve x=a(costheta+thetasintheta),y=a(sintheta-thetac...

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  8. The portion of the tangent drawn at any point on x^(2//3)+y^(2//3)=a^(...

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  9. The tangent at theta=pi//4 to the curve x=acos^3theta,y=asin^3theta me...

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  11. The sum of the intercepts on the coordinate axes of any tangent to sqr...

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  12. IF the tangent at any point P on the curve x^my^n=a^(m+n), mn ne 0 mee...

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  13. The tangent at any point f the curve x=at^3,y=at^4 divides the absciss...

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  14. If pand qare the lengths of the perpendiculars from the origin on the ...

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  15. If the tangent at any point on the curve x^4+y^4=a^4 cuts off intercep...

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  16. The sum of the squares o the intercepts on the coordinates axes of any...

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  17. If the tangent at any point on the curve x^(1//3)+y^(1//3)=a^(1//3)(ag...

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  18. If the sum of the squares of the intercepts on the axes cut off by the...

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  19. If the tangent at the point (at^2,at^3) on the curve ay^2=x^3 meets th...

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  20. If the tangent at (1,1) on y^2=x(2-x)^2 meets the curve again atpis

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