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The distance moved by the particle in ti...

The distance moved by the particle in time `t` is given by`s=t^3-12t^2+6t+8`. At the instant when its acceleration is zero, the velocity is

A

42

B

-42

C

48

D

-48

Text Solution

Verified by Experts

The correct Answer is:
B
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DIPTI PUBLICATION ( AP EAMET)-APPLICATIONS OF DIFFERENTIATION-EXERCISE 1C (RATE OF CHANGE)
  1. A stone projected vertically upward moves according to the law s=100t-...

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  2. A particle moves along a line according to the law s=t^4-5t^2+8. The i...

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  3. The distance moved by the particle in time t is given bys=t^3-12t^2+6...

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  4. A particle moves along a line according to the law s=4t^3-3t^2+2. At w...

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  5. The distance form a fixed point O of a particle pmoving in a straight ...

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  6. the distance s covered in time t by a particle moving along a straight...

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  7. The velocity v and the distance s travelled by a particle has the rela...

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  8. The velocity v of a point moving along a line when it is at a distance...

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  9. The distance travelled by a particle in time t is given by s=10t-7t^3....

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  10. For particle moving in a striaght line it is observed that tha distanc...

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  11. A particle is moving along a straight line according to the law s=16+4...

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  12. A particle moving according to the law s=6t-1/2t^3. At what time its v...

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  13. A particle is moving along a line according to the law s=t^3-3t^2+5. T...

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  14. A particle is moving in a straight line with the relation between the ...

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  15. The distance s feet travelled by a particle in time t seconds is given...

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  16. A stone is thrown vertically up and the height s reached in time t is ...

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  17. A stone thrown upwards, has its equation of motion s=490t-4.9t^2. The ...

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  18. A stone is projected vertically upwards with an intial velocity 112 ft...

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  19. A stone projected vertically upward moves according to the law s=48t-1...

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  20. A stone is thrown vertically up and the height s reached in time t is ...

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