Home
Class 12
MATHS
A particle is moving along a line accord...

A particle is moving along a line according to the law `s=t^3-3t^2+5`. The acceleration of the particle at the instant where the velocity is zero is

A

2 unit/`sec^2`

B

4 unit/`sec^2`

C

6 unit/`sec^2`

D

8 unit/`sec^2`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1D (MEAN VALUE THEOREMS)|28 Videos
  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1E (MAXIMA AND MINIMA)|221 Videos
  • APPLICATIONS OF DIFFERENTIATION

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 1B (TANGENT AND NORMAL)|205 Videos
  • ADDITION OF VECTORS

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 SET - 4|8 Videos
  • BINOMIAL THEOREM

    DIPTI PUBLICATION ( AP EAMET)|Exercise EXERCISE 2 (SPECIAL TYPE QUESTIONS) SET - 4|4 Videos

Similar Questions

Explore conceptually related problems

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle is moving along a line according s= f(t) = 8t + t^3 . Find acceleration at t = 2 sec.

A particle moves along a line according to the law s=4t^3-3t^2+2 . At what time will the acceleration be equal to 42 unit/ sec^2 ?

A particle is moving along a straight line according to the law s=16+48t-t^3 . The distance travelled by the particle before coming to rest at an instant is

A particle is moving along a line according s= f(t) = 8t + t^3 . Find the initial velocity

The displacement of a particle moving along the x-axis is given by equation x=2t^(3)-2"t"^(2)+60t+6 .The possible acceleration of the particle when its velocity is zero is

A particle moves according to law s=t^3-3t^2+3t+12 . The velocity when the acceleration is zero is

A particle is moving along a line according to s=f(t) =4t^(3)-3t^(2)+5t-1 where s is measured in meter and t is measured in seconds. Find the velocity and acceleration at time t. At what time the acceleration is zero.

A particle is moving along a line according s=f(t)=4t^3-3t^2+5t-1 where s is measured in meters and t is measured in seconds. Find the velocity and acceleration at time t. At what time the acceleration is zero.

DIPTI PUBLICATION ( AP EAMET)-APPLICATIONS OF DIFFERENTIATION-EXERCISE 1C (RATE OF CHANGE)
  1. A particle is moving along a straight line according to the law s=16+4...

    Text Solution

    |

  2. A particle moving according to the law s=6t-1/2t^3. At what time its v...

    Text Solution

    |

  3. A particle is moving along a line according to the law s=t^3-3t^2+5. T...

    Text Solution

    |

  4. A particle is moving in a straight line with the relation between the ...

    Text Solution

    |

  5. The distance s feet travelled by a particle in time t seconds is given...

    Text Solution

    |

  6. A stone is thrown vertically up and the height s reached in time t is ...

    Text Solution

    |

  7. A stone thrown upwards, has its equation of motion s=490t-4.9t^2. The ...

    Text Solution

    |

  8. A stone is projected vertically upwards with an intial velocity 112 ft...

    Text Solution

    |

  9. A stone projected vertically upward moves according to the law s=48t-1...

    Text Solution

    |

  10. A stone is thrown vertically up and the height s reached in time t is ...

    Text Solution

    |

  11. The displacement of a body of mass 100kg in a retilinear motion is giv...

    Text Solution

    |

  12. A car starts from rest and attains the speed of 10 km/hr repectively a...

    Text Solution

    |

  13. A particle moves on a line according to the law s=at^2+bt+c. If the di...

    Text Solution

    |

  14. The point pis moving with uniform velocity v along a straight line AB....

    Text Solution

    |

  15. If the rate of decrease of x^2/2-2x+5 is twice the decrease of x, then...

    Text Solution

    |

  16. If the rate of change in y=2x^3+3x^2-30x+7 is 6 times the rate of chan...

    Text Solution

    |

  17. At the point (2, 5) on the curve y=x^3-2x+1 the gradient of the curve ...

    Text Solution

    |

  18. The point on the parabola x^2=8y for which the abscissa and ordinate c...

    Text Solution

    |

  19. The point on the parabola y^2=4x for which the abscissa and ordinate c...

    Text Solution

    |

  20. A point on the parabola y^2=18x at which the ordinate increases at twi...

    Text Solution

    |