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The maximum value of the area of the tri...

The maximum value of the area of the triangle with vertices (a,0) ,(a ` cos theta, b sin theta`) , `(a cos theta, -b sin theta)` is

A

`(3sqrt(3 ab))/4`

B

`3sqrt(ab)`

C

`sqrt(3ab)/4`

D

`3sqrt(3ab)`

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The correct Answer is:
A
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DIPTI PUBLICATION ( AP EAMET)-APPLICATIONS OF DIFFERENTIATION-EXERCISE 1E (MAXIMA AND MINIMA)
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