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(Cos3alpha+isin3alpha)^(5)(cos4alpha-isi...

`(Cos3alpha+isin3alpha)^(5)(cos4alpha-isin4alpha)^(6)`

A

`cos9alpha-isin9alpha`

B

`cos9alpha+isin9alpha`

C

`cos8alpha-isin8alpha`

D

`cos8alpha+isin8alpha`

Text Solution

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Knowledge Check

  • If (sinalpha+icosalpha)^4(cos2alpha-isin2alpha)^(-2)=costheta+isintheta," then "theta=

    A
    0
    B
    `4alpha`
    C
    `6alpha`
    D
    `5alpha`

  • |(sin alpha, cos alpha),(cos alpha, -sin alpha)|=

    A
    1
    B
    -1
    C
    0
    D
    2

  • ((cosalpha-cos 3 alpha)(sin8alpha+sin 2alpha))/((sin 5alpha-sin alpha)(cos 4 alpha-cos 6alpha))=

    A
    `-1`
    B
    `-2`
    C
    `2`
    D
    `1`

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