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If on an average 5 precent of the output...

If on an average 5 precent of the output of a factory making certain parts is defective and that 200 units are in a packeage , then the probability that atmost 4 defective parts may be found in a package is

A

`e^(-10)[1+(100)/(1!)+(100^(2))/(2!)+(100^(3))/(3!)+(100^(4))/(4!)]`

B

`e^(-10)[1+(10)/(1!)+(10^(2))/(2!)+(10^(3))/(3!)+(10^(4))/(4!)]`

C

`[1+(10)/(1!)+(10^(2))/(2!)+(10^(3))/(3!)+(10^(4))/(4!)]`

D

`2e^(-10)[1+(20)/(1!)+(30^(2))/(2!)+(40^(3))/(3!)+(50^(4))/(4!)]`

Text Solution

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The correct Answer is:
B
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