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The equation of the ellipse whose foci a...

The equation of the ellipse whose foci are `(pm3,0)` and eccentricity 3/4 is

A

`x^(2)/16+y^(2)/9=1`

B

`x^(2)/16+y^(2)/7=1`

C

`x^(2)/9+y^(2)/16=1`

D

`x^(2)/7+y^(2)/16=1`

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Knowledge Check

  • The equation of the hyperbola whose foci are ( +- 5,0) and eccentricity 5/3 is

    A
    ` (x^(2))/( 9) -y^( 2)/( 16) =1`
    B
    ` ( x^(2) )/( 4) -( y^(2))/( 16) = 1`
    C
    ` (x^(2) )/( 9) +( y^(2)) /( 6) = 1 `
    D
    ` (x^(2))/( 4) +(y^(2))/( 16) = 1 `

  • The equation of the ellipse whose vertices are (2, 5), (2, -1) and eccentricity sqrt(5)/(3) is

    A
    `(x-2)^(2)/(9)+(y-2)^(2)/(4)=1`
    B
    `(x-2)^(2)/(9)+(y-2)^(2)/(16)=1`
    C
    `(x+2)^(2)/(16)+(y-2)^(2)/(36)=1`
    D
    `(x+2)^(2)/(36)+(y+3)^(2)/(16)=1`

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