If `log_30 3 = x, log_30 5 = y, then log_30 8 =`

STATEMENT-1 : Number of solution of log |x| = theta^(x) is two and STATEMENT-2 : If log_(30) 3 - a , log_(30) 5 = b "then" log_(30) 8 = 3 (1 - a - b) .

If log_(30)3=x,log_(30)5=y,thenlog_(30)8=

If log_(10)3=x and log_(30)5=y , then log_(30)8 is equal to

If log_30(3)=alpha and log_30(5)=beta, then log_30(8) is equal to

If log_(3) x log_(y) 3 log_(2) y = 5 , then x =

If log_(30)3=a and log_(30)5=b find the value of log_(30)8

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_6 30=1.898