Explain eohy in general(ii) `(A +- B)^2 !=A^2 + B^2 +- 2AB.`

If A and B are square matrices of the same order, explain, why in general (A+B)^2!=A^2+2A B+B^2 (ii) (A-B)^2!=A^2-2A B+B^2 (iii) (A+B)(A-B)!=A^2-B^2 .

If A and B are square matrices of the same order,explain,why in general (A+B)^(2)!=A^(2)+2AB+B^(2)( ii) (A-B)^(2)!=A^(2)-2AB+B^(2)( iii) (A+B)(A-B)!=A^(2)-B^(2)

(i)A^(2)-B^(2)!=(A+B)(A-B) Explain why in general( (0A?-8^(^^)@=(A+B)(A-B)

Assertion (A) : (A + B) ^(2) ne A^(2) + 2AB + B^(2) Reason (R) : Generally AB ne BA

Factorise the using the identity a ^(2) - 2 ab + b ^(2) = (a -b) ^(2). 4a ^(2) - 4 ab + b ^(2)

Let us simplify using formula:- (a+b)(a-b) (a^2 + ab + b^2) (a^2 - ab + b^2)

(ii) If a-b=3 and a^2 + b^2 = 29 , find ab .

State with reason, whether the following are true or false, A,B, and C are matrices of order 2 xx 2 (i) A.B=B.A (ii) A. (B.C)=(A.B).C (iii) (A+B)^2=A^2+2AB+B^2 (iv) A.(B+C)=A.B+A.C

a^3 - b^3 - 3a^2b+ 3ab^2, by, a^2 + b^2 - 2ab

If a = 2 and b = 3, find the value of (i) a + b (ii) a^(2) + ab (iii) ab - a^(2) (iv) 2a - 3b (v) 5a^(2) - 2ab (vi) a^(3) - b^(3)