|[b^(2)+c^(2),ab,ca],[ab,c^(2)+a^(2),bc],[ca,bc,a^(2)+b^(2)]|=4a^(2)b^(2)c^(2)

Prove the identities: |{:(b^(2)+c^(2),,ab,,ac),(ab,,c^(2)+a^(2),,bc),(ca,,bc,,a^(2)+b^(2)):}|=4a^2b^2c^2

Evaluate |[0,c,b] , [c,0,a] , [b,a,0]| hence show that |[0,c,b] , [c,0,a] , [b,a,0]|^2= |[b^2+c^2,ab,ac] , [ab,c^2+a^2,bc] , [ca,bc,a^2+b^2]|=4a^2b^2c^2

If a,b,c are non-zero real numbers then D=det[[b^(2)c^(2),bc,b+cc^(2)a^(2),ca,c+aa^(2)b^(2),ab,a+b]]=(A)abc(B)a^(2)b^(2)c^(2)(C)bc+ca+ab(D)0,

|[bc,ca,ab],[(b+c)^(2),(c+a)^(2),(a+b)^(2)],[a^(2),b^(2)c^(2)]|

Prove that |[(a+b)^(2),ca,bc],[ca,(b+c)^(2),ab],[bc,ab,(c+a)^(2)]|=2abc(a+b+c)^(3)

det[[bc-a^(2),ca-b^(2),ab-c^(2)ca-b^(2),ab-c^(2),bc-a^(2)ab-c^(2),bc-a^(2),ca-b^(2)]]=det[[a,b,cb,c,ac,a,b]]^(2)

Evaluate |{:(0,c,b),(c,0,a),(b,a,0):}| , hence show that . |{:(0,c,b),(c,0,a),(b,a,0):}|^2=|{:(b^2+c^2," "ab," "ac),(" "ab,c^2+a^2," "bc),(" "ca," "bc,a^2+b^2):}|=4a^2b^2c^2

Show that |{:(bc-a^(2),,ca-b^(2),,ab-c^(2)),(ca-b^(2),,ab-c^(2),,bc-a^(2)),(ab-c^(2),,bc-a^(2),,ca-b^(2)):}| |{:(a^(2),,c^(2),,2ca-b^(2)),(2ab-c^(2),,b^(2),,a^(2)),(b^(2),,2ac-a^(2),,c^(2)):}|.