" (ii) "quad (7sqrt(3)-5sqrt(2))/(sqrt(48)+sqrt(18))

(4sqrt(3)+5sqrt(2))/(sqrt(48)+sqrt(18))

Simplify by raationalising the denominator. (i) (7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)) (ii) (2sqrt(6) -sqrt(5))/(3sqrt(5)-2sqrt(6))

Rationalise the denominator and simplify: (i) (4sqrt(3)+5sqrt(2))/(sqrt(48)+\ sqrt(18)) (ii) (2sqrt(3)-\ sqrt(5))/(2\ sqrt(2)+\ 3sqrt(3))

(2sqrt(7))/(sqrt(5)-sqrt(3))

Rationales the denominator and simplify: (4sqrt(3)+5sqrt(2))/(sqrt(48)+sqrt(18))( ii) (2sqrt(3)-sqrt(5))/(2sqrt(2)+3sqrt(3))

Rationales the denominator and simplify: (sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2)) (ii) (5+2sqrt(3))/(7+4sqrt(3)) (iii) (1+sqrt(2))/(3-2sqrt(2)) (2sqrt(6)-sqrt(5))/(3sqrt(5)-2sqrt(6)) (v) (4sqrt(3)+5sqrt(2))/(sqrt(48)+sqrt(18)) (vi) (2sqrt(3)-sqrt(5))/(2sqrt(3)+3sqrt(3))

If (4 sqrt(3) + 5 sqrt(2))/(sqrt(48 ) + sqrt(18))= a + bsqrt(6) , then the value of a and b are respectively

Evaluate (sqrt(5)-sqrt(3))/(sqrt(2)+sqrt(7))

(5sqrt(2)xx7sqrt(7))/(3sqrt(27)xx sqrt(125))=

Rationalize the denominator of (5sqrt(3)-3sqrt(2))/(sqrt(108)+sqrt(18))