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Given that 6 is a divisor of r and r is ...

Given that 6 is a divisor of r and r is a factor of s, is 6 a factor of s?

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To determine whether 6 is a factor of s given that 6 is a divisor of r and r is a factor of s, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the first statement**: - We know that 6 is a divisor of r. This means that r can be expressed as: \[ r = 6n \] where n is some integer. 2. **Understanding the second statement**: - The second statement tells us that r is a factor of s. This means that s can be expressed as: \[ s = rm \] where m is some integer. 3. **Substituting the expression for r into the equation for s**: - Now, we can substitute the expression for r from the first statement into the second statement: \[ s = (6n)m \] - This simplifies to: \[ s = 6(nm) \] - Here, (nm) is also an integer since the product of two integers is an integer. 4. **Conclusion**: - Since s can be expressed as \(s = 6k\) where \(k = nm\) (an integer), we conclude that 6 is indeed a factor of s. ### Final Answer: Yes, 6 is a factor of s.
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