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Boys and girls in a class are writing le...

Boys and girls in a class are writing letters. There are twice as many girls as boys in the class, and each girl writes 3 more letters than each boy. If boys write 24 of the 90 total letters written by the class, how many letters does each boy write?

A

3

B

4

C

5

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can break it down as follows: ### Step 1: Define Variables Let: - \( b \) = number of boys in the class - \( g \) = number of girls in the class - \( x \) = number of letters written by each boy ### Step 2: Establish Relationships According to the problem: - There are twice as many girls as boys: \[ g = 2b \] - Each girl writes 3 more letters than each boy: \[ \text{Letters written by each girl} = x + 3 \] ### Step 3: Total Letters Written We know the total number of letters written by boys and girls: - Boys write 24 letters, so: \[ bx = 24 \] - The total number of letters written by girls is: \[ \text{Total letters by girls} = g \times (\text{letters per girl}) = g \times (x + 3) \] - The total number of letters written by the class is 90: \[ \text{Total letters} = \text{Letters by boys} + \text{Letters by girls} = 24 + g(x + 3) = 90 \] ### Step 4: Substitute for Girls Substituting \( g = 2b \) into the total letters equation: \[ 24 + 2b(x + 3) = 90 \] This simplifies to: \[ 2b(x + 3) = 90 - 24 \] \[ 2b(x + 3) = 66 \] ### Step 5: Solve for \( bx \) From \( bx = 24 \), we can express \( b \) in terms of \( x \): \[ b = \frac{24}{x} \] ### Step 6: Substitute \( b \) into the Equation Now substitute \( b \) into the equation \( 2b(x + 3) = 66 \): \[ 2\left(\frac{24}{x}\right)(x + 3) = 66 \] This simplifies to: \[ \frac{48(x + 3)}{x} = 66 \] ### Step 7: Clear the Fraction Multiply both sides by \( x \): \[ 48(x + 3) = 66x \] Expanding gives: \[ 48x + 144 = 66x \] ### Step 8: Rearrange the Equation Rearranging the equation: \[ 144 = 66x - 48x \] \[ 144 = 18x \] ### Step 9: Solve for \( x \) Dividing both sides by 18: \[ x = \frac{144}{18} = 8 \] ### Conclusion Thus, each boy writes **8 letters**. ---
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