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A rectangle has a perimeter of 16 meters...

A rectangle has a perimeter of 16 meters and an area of 15 square meters. What is the longest of the side lengths, in meters, of the rectangle?

A

3

B

5

C

10

D

15

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the dimensions of a rectangle given its perimeter and area. **Step 1: Set up the equations for perimeter and area.** The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2 \times (l + b) \] where \( l \) is the length and \( b \) is the breadth. Given that the perimeter is 16 meters, we can write: \[ 2 \times (l + b) = 16 \] Dividing both sides by 2, we get: \[ l + b = 8 \quad \text{(Equation 1)} \] The area \( A \) of a rectangle is given by the formula: \[ A = l \times b \] Given that the area is 15 square meters, we can write: \[ l \times b = 15 \quad \text{(Equation 2)} \] **Step 2: Express one variable in terms of the other.** From Equation 1, we can express \( b \) in terms of \( l \): \[ b = 8 - l \] **Step 3: Substitute into the area equation.** Now, we substitute \( b \) in Equation 2: \[ l \times (8 - l) = 15 \] Expanding this gives: \[ 8l - l^2 = 15 \] Rearranging the equation, we get: \[ l^2 - 8l + 15 = 0 \] **Step 4: Solve the quadratic equation.** To solve the quadratic equation \( l^2 - 8l + 15 = 0 \), we can factor it: \[ (l - 3)(l - 5) = 0 \] Setting each factor to zero gives us: \[ l - 3 = 0 \quad \Rightarrow \quad l = 3 \] \[ l - 5 = 0 \quad \Rightarrow \quad l = 5 \] **Step 5: Find the corresponding breadth values.** Using \( l = 3 \): \[ b = 8 - 3 = 5 \] Using \( l = 5 \): \[ b = 8 - 5 = 3 \] Thus, the dimensions of the rectangle are 3 meters and 5 meters. **Step 6: Identify the longest side.** The longest side length of the rectangle is: \[ \text{Longest side} = 5 \text{ meters} \] So, the final answer is: \[ \text{The longest side length of the rectangle is } 5 \text{ meters.} \] ---
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Knowledge Check

  • The area of a rectangle is 300 square meters, and its length is 3 times its width. How many meters wide is the rectangle?

    A
    10
    B
    30
    C
    50
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  • A rectangle is 5 times as wide as it is long. The area of the rectangle is 320 square feet. What is the perimeter of the rectangle , in feet ?

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  • A homeowners' association limits the dimensions of the pools that it will allow in a particular subdivision. The bylaws state that permits will only be granted for pools shaped like rectangular prisms, for which the sum of the length of the pool and the perimeter of the vertical side containing the ladder cannot exceed 200 meters. the perimeters of the ladder side is determined using the width and the depth of the pool . IF a pool has a length of 75 meters and its width is 1.5 times its depth, which of the following shows the allowable depth a, in meters, of the pool?

    A
    `0 lt a lt 62 1/2`
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