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If xy=6,yz=10, xz=15, and x gt0, then xy...

If `xy=6,yz=10, xz=15, and x gt0`, then `xyz=`

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To solve the problem step by step, we start with the given equations: 1. **Given Equations:** - \( xy = 6 \) (1) - \( yz = 10 \) (2) - \( xz = 15 \) (3) - \( x > 0 \) 2. **Expressing \( z \) in terms of \( x \) and \( y \):** From equation (1), we can express \( y \) in terms of \( x \): \[ y = \frac{6}{x} \] 3. **Substituting \( y \) into equation (2):** Now, substitute \( y \) into equation (2): \[ \left(\frac{6}{x}\right)z = 10 \] Rearranging gives: \[ z = \frac{10x}{6} = \frac{5x}{3} \] 4. **Substituting \( z \) into equation (3):** Now, substitute \( z \) into equation (3): \[ x\left(\frac{5x}{3}\right) = 15 \] Simplifying this gives: \[ \frac{5x^2}{3} = 15 \] 5. **Solving for \( x^2 \):** Multiply both sides by 3 to eliminate the fraction: \[ 5x^2 = 45 \] Now, divide both sides by 5: \[ x^2 = 9 \] Taking the square root gives: \[ x = 3 \quad (\text{since } x > 0) \] 6. **Finding \( y \):** Now that we have \( x \), we can find \( y \): \[ y = \frac{6}{x} = \frac{6}{3} = 2 \] 7. **Finding \( z \):** Now we can find \( z \) using the expression we derived: \[ z = \frac{5x}{3} = \frac{5 \cdot 3}{3} = 5 \] 8. **Calculating \( xyz \):** Finally, we can calculate \( xyz \): \[ xyz = x \cdot y \cdot z = 3 \cdot 2 \cdot 5 = 30 \] Thus, the value of \( xyz \) is \( 30 \).
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