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(1)/(x^(3)),(1)/(x^(2)), (1)/(x),x^(2),x...

`(1)/(x^(3)),(1)/(x^(2)), (1)/(x),x^(2),x^(3)`
If `-1ltxlt0`, what is the median of the five numbers in the list above?

A

`(1)/(x^(2))`

B

`(1)/(x^(2))`

C

`(1)/(x)`

D

`x^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the median of the given numbers \(\frac{1}{x^3}, \frac{1}{x^2}, \frac{1}{x}, x^2, x^3\) when \(-1 < x < 0\), we will follow these steps: ### Step 1: Understand the range of \(x\) Given that \(x\) is in the range \(-1 < x < 0\), we know that \(x\) is negative. ### Step 2: Analyze each expression We will evaluate each expression in the list: - \(\frac{1}{x^3}\) - \(\frac{1}{x^2}\) - \(\frac{1}{x}\) - \(x^2\) - \(x^3\) ### Step 3: Determine the signs and order of the expressions 1. **For \(\frac{1}{x^3}\)**: Since \(x\) is negative, \(x^3\) is also negative, making \(\frac{1}{x^3}\) positive. 2. **For \(\frac{1}{x^2}\)**: \(x^2\) is positive (since squaring a negative number yields a positive result), hence \(\frac{1}{x^2}\) is also positive. 3. **For \(\frac{1}{x}\)**: Since \(x\) is negative, \(\frac{1}{x}\) is negative. 4. **For \(x^2\)**: As mentioned, \(x^2\) is positive. 5. **For \(x^3\)**: \(x^3\) is negative. ### Step 4: Order the expressions from least to greatest From the analysis: - Negative values: \(x^3\) and \(\frac{1}{x}\) - Positive values: \(x^2\), \(\frac{1}{x^2}\), and \(\frac{1}{x^3}\) Now we can order them: 1. \(x^3\) (most negative) 2. \(\frac{1}{x}\) (less negative) 3. \(x^2\) (first positive) 4. \(\frac{1}{x^2}\) (greater positive) 5. \(\frac{1}{x^3}\) (largest positive) So the ordered list is: \[ x^3, \frac{1}{x}, x^2, \frac{1}{x^2}, \frac{1}{x^3} \] ### Step 5: Find the median The median is the middle value in an ordered list. Since we have 5 numbers, the median is the 3rd number. From our ordered list: - 1st: \(x^3\) - 2nd: \(\frac{1}{x}\) - 3rd: \(x^2\) (this is the median) ### Final Answer The median of the five numbers is: \[ \boxed{x^2} \]
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