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Michael needs a printing job completed. ...

Michael needs a printing job completed. Photoperfect Print Shop charges a fixed fee of `$3` for the print job and 5 cents per page. Bargain Printing charges a fixed fee of `$2` for the point job and 7 cents per page. P represents the number of pages being printed, what are all values of p for which Photoperfect Print Shop's total charge is less than Bargain Printing's total charge.

A

`plt20`

B

`20leple35`

C

`35leple50`

D

`pgt50`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to compare the total charges of Photoperfect Print Shop and Bargain Printing based on the number of pages (P) being printed. ### Step-by-step Solution: 1. **Define the Charges**: - **Photoperfect Print Shop**: Charges a fixed fee of $3 and 5 cents per page. - **Bargain Printing**: Charges a fixed fee of $2 and 7 cents per page. 2. **Convert Cents to Dollars**: - Since 1 cent = $0.01, we convert the per-page charges: - Photoperfect's charge per page: \(5 \text{ cents} = 5 \times 0.01 = 0.05\) dollars. - Bargain's charge per page: \(7 \text{ cents} = 7 \times 0.01 = 0.07\) dollars. 3. **Write the Total Charge Equations**: - For Photoperfect Print Shop: \[ \text{Charge}_{\text{Photoperfect}} = 3 + 0.05P \] - For Bargain Printing: \[ \text{Charge}_{\text{Bargain}} = 2 + 0.07P \] 4. **Set Up the Inequality**: - We want to find when Photoperfect's charge is less than Bargain's charge: \[ 3 + 0.05P < 2 + 0.07P \] 5. **Simplify the Inequality**: - Subtract 2 from both sides: \[ 1 + 0.05P < 0.07P \] - Subtract \(0.05P\) from both sides: \[ 1 < 0.02P \] 6. **Solve for P**: - Divide both sides by 0.02: \[ P > \frac{1}{0.02} \] - Calculate \(\frac{1}{0.02}\): \[ P > 50 \] ### Conclusion: The values of \(P\) for which Photoperfect Print Shop's total charge is less than Bargain Printing's total charge are: \[ P > 50 \]
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