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Solve the following quantitative compari...

Solve the following quantitative comparison problem by plugging in the number 0,1,2, -2, and `1//2` in that order - when possible.
`{:("Column A",x = y != 0,"Column B"),(0,,x//y):}`

A

If column A is larger

B

If column B is larger

C

If the columns are equal

D

If there is not enough information to decide

Text Solution

AI Generated Solution

The correct Answer is:
To solve the quantitative comparison problem, we need to evaluate the two columns based on the given conditions. Let's break it down step by step. ### Step 1: Understand the Columns - **Column A**: The value is `0`. - **Column B**: The value is `x/y`, where `x = y` and `x` and `y` are not equal to `0`. ### Step 2: Plug in Values We will plug in the values `0`, `1`, `2`, `-2`, and `1/2` into the columns while keeping in mind that `x` and `y` must be equal and not equal to `0`. #### Case 1: Plugging in `0` - Since `x` and `y` cannot be `0`, we cannot use this value. #### Case 2: Plugging in `1` - Let `x = 1` and `y = 1`. - Column A = `0` - Column B = `x/y = 1/1 = 1` - Comparison: Column A (0) < Column B (1) #### Case 3: Plugging in `2` - Let `x = 2` and `y = 2`. - Column A = `0` - Column B = `x/y = 2/2 = 1` - Comparison: Column A (0) < Column B (1) #### Case 4: Plugging in `-2` - Let `x = -2` and `y = -2`. - Column A = `0` - Column B = `x/y = -2/-2 = 1` - Comparison: Column A (0) < Column B (1) #### Case 5: Plugging in `1/2` - Let `x = 1/2` and `y = 1/2`. - Column A = `0` - Column B = `x/y = (1/2)/(1/2) = 1` - Comparison: Column A (0) < Column B (1) ### Step 3: Conclusion In all valid cases where we plugged in values for `x` and `y`, Column B is always greater than Column A. Therefore, the answer is: **Column B is larger than Column A.** ### Final Answer **Column B is larger.**
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