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{:("Column A"," ","Column B"),("T...

`{:("Column A"," ","Column B"),("The clockwise angle made by the hour hand and the minute hant at 12:15 pm",,"The anticlockwise angle made by the hour hand and the minute hand at 12:45 pm"):}`

A

If column A is larger

B

If column B is larger

C

If the columns are equal

D

If there is not enough information to decide

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the angles made by the hour and minute hands of a clock at two different times: 12:15 PM and 12:45 PM. ### Step-by-Step Solution: **Step 1: Calculate the angle for Column A (12:15 PM)** 1. **Position of the Hour Hand at 12:15 PM:** - The hour hand moves 30 degrees for each hour (360 degrees / 12 hours). - At 12:15 PM, the hour hand is a quarter of the way between 12 and 1. - Therefore, the hour hand's position is: \[ \text{Angle of hour hand} = 0 + \left(\frac{15}{60} \times 30\right) = 0 + 7.5 = 7.5 \text{ degrees} \] 2. **Position of the Minute Hand at 12:15 PM:** - The minute hand moves 6 degrees for each minute (360 degrees / 60 minutes). - At 15 minutes, the minute hand's position is: \[ \text{Angle of minute hand} = 15 \times 6 = 90 \text{ degrees} \] 3. **Calculate the Clockwise Angle:** - The clockwise angle between the hour hand and minute hand is: \[ \text{Clockwise angle} = \text{Angle of minute hand} - \text{Angle of hour hand} = 90 - 7.5 = 82.5 \text{ degrees} \] **Step 2: Calculate the angle for Column B (12:45 PM)** 1. **Position of the Hour Hand at 12:45 PM:** - At 12:45 PM, the hour hand is three-quarters of the way between 12 and 1. - Therefore, the hour hand's position is: \[ \text{Angle of hour hand} = 0 + \left(\frac{45}{60} \times 30\right) = 0 + 22.5 = 22.5 \text{ degrees} \] 2. **Position of the Minute Hand at 12:45 PM:** - At 45 minutes, the minute hand's position is: \[ \text{Angle of minute hand} = 45 \times 6 = 270 \text{ degrees} \] 3. **Calculate the Anticlockwise Angle:** - The anticlockwise angle between the hour hand and minute hand is: \[ \text{Anticlockwise angle} = 360 - (\text{Angle of minute hand} - \text{Angle of hour hand}) = 360 - (270 - 22.5) = 360 - 247.5 = 112.5 \text{ degrees} \] ### Conclusion: - Column A (12:15 PM) = 82.5 degrees - Column B (12:45 PM) = 112.5 degrees Thus, the angles are not equal.
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