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Let C and K be constants. If x^2 + Kx + ...

Let C and K be constants. If `x^2 + Kx + 5` factors into `(x + 1)(x + C)`, the value of K is

A

`0`

B

`5`

C

`6`

D

`8`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( K \) given that the quadratic expression \( x^2 + Kx + 5 \) factors into \( (x + 1)(x + C) \). ### Step-by-step Solution: 1. **Set up the equation**: We start with the equation given in the problem: \[ x^2 + Kx + 5 = (x + 1)(x + C) \] 2. **Expand the right-hand side**: We will expand the product on the right side: \[ (x + 1)(x + C) = x^2 + Cx + x + 1 = x^2 + (C + 1)x + 1 \] 3. **Equate coefficients**: Now we can equate the coefficients from both sides of the equation: \[ x^2 + Kx + 5 = x^2 + (C + 1)x + 1 \] From this, we can derive two equations by comparing coefficients: - Coefficient of \( x \): \( K = C + 1 \) (Equation 1) - Constant term: \( 5 = 1 \) (This is incorrect, we should have \( 5 = C \)) (Equation 2) 4. **Solve for \( C \)**: From Equation 2, we have: \[ C = 5 \] 5. **Substitute \( C \) into Equation 1**: Now we substitute \( C \) back into Equation 1 to find \( K \): \[ K = C + 1 = 5 + 1 = 6 \] 6. **Final answer**: Therefore, the value of \( K \) is: \[ \boxed{6} \]
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