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A system of equation is as shown below ...

A system of equation is as shown below
`x + l = 6`
`x - m = 5`
`x + p = 4`
`x - q = 3`
What is the value of `l + m + p + q` ?

A

2

B

3

C

4

D

5

Text Solution

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The correct Answer is:
To solve the system of equations given by: 1. \( x + l = 6 \) (Equation 1) 2. \( x - m = 5 \) (Equation 2) 3. \( x + p = 4 \) (Equation 3) 4. \( x - q = 3 \) (Equation 4) we need to find the value of \( l + m + p + q \). ### Step-by-Step Solution: **Step 1: Isolate the variables \( l, m, p, \) and \( q \)** From Equation 1: \[ l = 6 - x \] From Equation 2: \[ m = x - 5 \] From Equation 3: \[ p = 4 - x \] From Equation 4: \[ q = x - 3 \] **Step 2: Substitute the expressions for \( l, m, p, \) and \( q \)** Now we can express \( l + m + p + q \) in terms of \( x \): \[ l + m + p + q = (6 - x) + (x - 5) + (4 - x) + (x - 3) \] **Step 3: Simplify the expression** Combine the terms: \[ l + m + p + q = 6 - x + x - 5 + 4 - x + x - 3 \] Notice that the \( -x \) and \( +x \) terms cancel out: \[ l + m + p + q = 6 - 5 + 4 - 3 \] Now, simplify the constants: \[ l + m + p + q = 1 + 1 = 2 \] ### Final Answer: Thus, the value of \( l + m + p + q \) is: \[ \boxed{2} \]
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