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In 2012, the arithmetic mean of the annu...

In 2012, the arithmetic mean of the annual incomes of Jack and Jill was $3800. The arithmetic mean of the annual incomes of Jill and Jess was $4800, and the arithmetic mean of the annual incomes of Jess and Jack was $5800. What of the incomes of the three?

A

4000

B

4200

C

4400

D

4800

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information given about the arithmetic means of the incomes of Jack, Jill, and Jess. ### Step 1: Set up the equations based on the given means. 1. **Jack and Jill**: The arithmetic mean of Jack (J) and Jill (Ji) is $3800. \[ \frac{J + Ji}{2} = 3800 \] Multiplying both sides by 2 gives: \[ J + Ji = 7600 \quad \text{(Equation 1)} \] 2. **Jill and Jess**: The arithmetic mean of Jill (Ji) and Jess (Je) is $4800. \[ \frac{Ji + Je}{2} = 4800 \] Multiplying both sides by 2 gives: \[ Ji + Je = 9600 \quad \text{(Equation 2)} \] 3. **Jess and Jack**: The arithmetic mean of Jess (Je) and Jack (J) is $5800. \[ \frac{Je + J}{2} = 5800 \] Multiplying both sides by 2 gives: \[ Je + J = 11600 \quad \text{(Equation 3)} \] ### Step 2: Combine the equations to find the total income. Now we have three equations: - Equation 1: \( J + Ji = 7600 \) - Equation 2: \( Ji + Je = 9600 \) - Equation 3: \( Je + J = 11600 \) To find the total income of Jack, Jill, and Jess, we can add all three equations together: \[ (J + Ji) + (Ji + Je) + (Je + J) = 7600 + 9600 + 11600 \] This simplifies to: \[ 2J + 2Ji + 2Je = 28800 \] ### Step 3: Solve for the total income of Jack, Jill, and Jess. Dividing the entire equation by 2 gives: \[ J + Ji + Je = 14400 \quad \text{(Equation 4)} \] ### Step 4: Calculate the arithmetic mean of their incomes. The arithmetic mean (AM) of the incomes of Jack, Jill, and Jess is given by: \[ AM = \frac{J + Ji + Je}{3} \] Substituting the value from Equation 4: \[ AM = \frac{14400}{3} = 4800 \] ### Final Answer: The arithmetic mean of the incomes of Jack, Jill, and Jess is **$4800**. ---
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