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{:("Column A","a and b are positive".(a ...

`{:("Column A","a and b are positive".(a +6) : (b +6) = 5 : 6 ,"Column B"),((a + 10)/(b + 10),,1):}`

A

If column A is larger

B

If column B is larger

C

If the columns are equal

D

If there is not enough information to decide

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given ratios and derive the relationship between the two columns. ### Step-by-Step Solution: 1. **Understanding the Given Ratio**: We have the ratio \((a + 6) : (b + 6) = 5 : 6\). This means that: \[ \frac{a + 6}{b + 6} = \frac{5}{6} \] 2. **Cross-Multiplying**: We can cross-multiply to eliminate the fraction: \[ 6(a + 6) = 5(b + 6) \] Expanding both sides gives: \[ 6a + 36 = 5b + 30 \] 3. **Rearranging the Equation**: Rearranging the equation to isolate \(a\) and \(b\): \[ 6a - 5b = 30 - 36 \] Simplifying this results in: \[ 6a - 5b = -6 \] 4. **Adding 24 to Both Sides**: To facilitate the next steps, we add 24 to both sides: \[ 6a - 5b + 24 = 18 \] This can be rearranged as: \[ 6(a + 4) - 5b = 18 \] 5. **Dividing by \(b + 10\)**: We want to express \(\frac{a + 10}{b + 10}\). First, we can express \(a + 10\) in terms of \(b + 10\): \[ 6(a + 10) = 6a + 60 \] From our previous equation, we can substitute \(6a\): \[ 6a = 5b + 30 \] Thus: \[ 6(a + 10) = 5b + 30 + 60 = 5b + 90 \] 6. **Finding the Expression**: Now, we can express \(\frac{a + 10}{b + 10}\): \[ \frac{a + 10}{b + 10} = \frac{5b + 90}{b + 10} \] 7. **Simplifying the Expression**: We can simplify this expression: \[ \frac{5b + 90}{b + 10} = 5 + \frac{40}{b + 10} \] 8. **Analyzing the Result**: Since \(b\) is positive, \(b + 10\) is also positive. Therefore, \(\frac{40}{b + 10}\) will always be positive. This means: \[ \frac{a + 10}{b + 10} = 5 + \frac{40}{b + 10} > 5 \] 9. **Comparing with Column B**: Column B is simply 1. Since \(5 + \frac{40}{b + 10} > 5\), it is clear that: \[ \frac{a + 10}{b + 10} > 1 \] ### Conclusion: Thus, we conclude that Column A is greater than Column B.
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