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{:("Column A" , "12 students from sectio...

`{:("Column A" , "12 students from section A and 15 students from section B failed an Anthropolgy exam. Thus, an equal percentage of attendees failed the exam from either section","ColumnB"),("Number of attendees for the exam from section A",,"Number of attendees for the exam from section B"):}`

A

If column A is larger

B

If column B is larger

C

If the columns are equal

D

If there is not enough information to decide

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will denote the number of attendees from section A as \( a \) and from section B as \( b \). We know the following: - 12 students from section A failed the exam. - 15 students from section B failed the exam. - An equal percentage of attendees failed the exam from both sections. ### Step 1: Set up the equations based on the given information From the information provided, we can express the number of students who failed in terms of the total number of attendees and the percentage of students who failed. For section A: \[ \text{Number of students who failed} = \frac{a \cdot x}{100} = 12 \] For section B: \[ \text{Number of students who failed} = \frac{b \cdot x}{100} = 15 \] ### Step 2: Solve for \( a \) and \( b \) From the equation for section A, we can rearrange it to find \( a \): \[ a = \frac{12 \cdot 100}{x} = \frac{1200}{x} \] From the equation for section B, we can rearrange it to find \( b \): \[ b = \frac{15 \cdot 100}{x} = \frac{1500}{x} \] ### Step 3: Compare \( a \) and \( b \) Now we have: \[ a = \frac{1200}{x} \quad \text{and} \quad b = \frac{1500}{x} \] Since the denominators are the same, we can compare the numerators: \[ 1200 \quad \text{and} \quad 1500 \] Clearly, \( 1500 > 1200 \), which implies: \[ b > a \] ### Conclusion Thus, the number of attendees from section B who took the exam is greater than the number of attendees from section A. Therefore, we conclude that: **Column B is larger than Column A.** The correct option is **option 2**. ---
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