Home
Class 12
MATHS
What is the rangle of 2, 8, 1, -6, pi, 1...

What is the rangle of `2, 8, 1, -6, pi, 1//2` ?

Text Solution

AI Generated Solution

The correct Answer is:
To find the range of the data points `2, 8, 1, -6, π, 1/2`, we can follow these steps: ### Step 1: Identify the Data Points The data points we have are: - 2 - 8 - 1 - -6 - π (approximately 3.14) - 1/2 (which is 0.5) ### Step 2: Arrange the Data Points in Ascending Order To find the range, we first need to arrange these numbers in ascending order: - -6 - 1/2 (0.5) - 1 - 2 - π (approximately 3.14) - 8 ### Step 3: Identify the Lowest and Highest Values From the ordered list, we can see: - The lowest value is -6 - The highest value is 8 ### Step 4: Calculate the Range The range is calculated as the difference between the highest and lowest values: \[ \text{Range} = \text{Highest Value} - \text{Lowest Value} \] Substituting the values we found: \[ \text{Range} = 8 - (-6) \] This simplifies to: \[ \text{Range} = 8 + 6 = 14 \] ### Final Answer The range of the data points `2, 8, 1, -6, π, 1/2` is **14**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the principal value of cos^(-1)cos((2pi)/3)+sin^(-1)sin((2pi)/3)?

What is the value of cos^(-1)(cos(2pi)/3)+sin^(-1)(sin(2pi)/3) ?

What is the principal value of cos^(-1)(cos(("2pi")/3))+sin^(-1)(sin(("2pi")/3))?

If tan^(-1)(x^2+3|x|-4)+cot^(-1)(4pi+sin^(-1)s in 14)=pi/2, t h e n the value of sin^(-1)2x is 6-2pi (b) 2pi-6 pi-3 (d) 3-pi

If int_0^a1/(1+4x^2)dx=\ pi/8 , then a equals a. pi/2 b. pi/4 c. 1/2 d. 1

If lim_(x->0)[1+x1n(1+b^2)]^(1/x)=2bsin^2theta,b >0 ,where theta in (-pi,pi], then the value of theta is (a) +-pi/4 (b) +-pi/3 (c) +-pi/6 (d) +-pi/2

If tan^(-1)(x^2+3|x|-4)+cot^(-1)(4pi+sin^(-1)sin 14)=pi/2, t h e n the value of sin^(-1)sin2x is (a) 6-2pi (b) 2pi-6 (c) pi-3 (d) 3-pi

Find the mode in each of the following data collection. 8,6,7,6,5,4, (1)/(2), 7 (1)/(2), 6 (1)/(2), 8 (1)/(2), 10,7,5,5(1)/(2), 8,9 7,5,6,8 (1)/(2),6

The value of cos^(-1)sqrt(2/3)-cos^(-1)((sqrt(6)+1)/(2sqrt(3))) is equal to (A) pi/3 (B) pi/4 (C) pi/2 (D) pi/6

What should be added to ((5)/(6) - (7)/(8)) to get (1)/(2) ?