`c o s e c2A+cot2A=?`

Prove: cot^2A cos e c^2B-cot^2B cos e c^2A=cot^2A-cot^2B .

Evaluate: "c o s e c"{cot^(-1)(-4/3)}

Find the principal values of each of the following: (i) "c o s e c"^(-1)(2/(sqrt(3))) (ii) "c o s e c"^(-1)(2cos(2/3pi))

Find the principal values of each of the following: (i) "c o s e c"^(-1)(2/(sqrt(3))) (ii) "c o s e c"^(-1)(2cos(2/3pi))

Prove that: ((1+tan^2theta)cottheta)/(c o s e c^2theta)=tantheta

If the angles of ∆ABC are in ratio 1:1:2, respectively (the largest angle being angle C), then the value of s e c A c o s e c B secAcosecB - t a n A c o t B tanAcotB is (a) 0 (b) 1/2 (c) 1 (d) √3/2

int(sec^2x)/(c o s e c^2x)dx

The value of cot(c o s e c^(- 1)5/3+tan^(- 1)(2/3))i s

Prove the following identities: cot^4theta+cot^2theta=cos e c^4theta-"c o s e c"^2"theta"

Let O be a point inside a triangle A B C such that /_O A B=/_O B C=/_O C A=omega , then show that: cotomega=cotA+cotB+cot C Cos e c^2omega=cos e c^2A+cos e c^2B+cos e c^2C