" (i) "(4sqrt(7)-6sqrt(3))/(4sqrt(3)+2sqrt(7))" (NGBRT IBxemplar) "

(sqrt(7)+2sqrt(3))(sqrt(7)-2sqrt(3))

(5sqrt(7)+2sqrt(7))(6sqrt(7)+3sqrt(7))=?

4sqrt(3)-7sqrt(12)+2sqrt(75)=

(5+2sqrt(3))/(7+4sqrt(3))=a-b sqrt(3)

(5+2sqrt(3))/(7+4sqrt(3))=a-b sqrt(3)

If a=(4sqrt(6))/(sqrt(2)+sqrt(3))

4sqrt7xx2sqrt3 =

sqrt(-sqrt(3)+sqrt(3+8sqrt(7+4sqrt(3))))=

sqrt(7+4sqrt3) - sqrt(7-4sqrt3) =

Add (i) (2sqrt(3)-5sqrt(2)) and (sqrt(3) + 2sqrt(2)) (ii) (2sqrt(2) + 5sqrt(3) - 7 sqrt(5) and (3sqrt(3)-sqrt(2) + sqrt(5)) (iii) ((2)/(3) sqrt(7) -(1)/(2)sqrt(2)+6sqrt(11)) and ((1)/(3)sqrt(7) + (3)/(2)-sqrt(11))