25x(x+1)=41=-4

Solve by factorization: 25x(x+1)=-4

A ray of light is incident along a line which meets another line,7x-y+1=0, at the point (0,1). The ray isthen reflected from this point along the line,y+2x=1. Then the equation of the line of incidence of the ray of light is (A) 41x+38y-38=0 (B) 41x-38y+38=0( C) 41x+25y-25=0 (D) 41x-25y+25=0

If 5x +1/(3x)=4 , then what is the value of 9x^2+1/(25x^2) ? यदि 5x +1/(3x)=4 है, तो 9x^2+1/(25x^2) का मान क्या होगा ?

If f(x) =tan^(-1)((x)/(1+20x^(2))) , show that, f'(x)=(5)/(1+25x^(2))-(4)/(1+16x^(2))

The equation of the ellipse having a vertex at (6,1) a focus at (4,1) and the eccentricity (3)/(5) is 1) ((x-1)^(2))/(16)+((y-1)^(2))/(25)=1 (2) ((x-1)^(2))/(25)+((y-1)^(2))/(16)=1 3) ((x+1)^(2))/(25)+((y+1)^(2))/(16)=1 (4) ((x+1)^(2))/(16)+((y+1)^(2))/(25)=1

The function f(x)=4x^5-25x^4+40x^3-10 has

Factorize each of the following expressions: 36l^(2)-(m+n)^(2)(2)25x^(4)y^(4)-1a^(4)-(1)/(b^(4))(4)x^(3)-144x(x-4y)^(2)-625(6)9(a-b)^(2)-100(x-y)^(2)

f(x)=x^(4)-25x^(2) k(x)=(1)/(x^(3)+3x^(2)-10x) Which of the following expressions is equivalent to f(x) . k(x),for xgt2 ?