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[[-4,4,4],[-7,1,3],[5,-3,-1]][[1,-1,10],...

[[-4,4,4],[-7,1,3],[5,-3,-1]][[1,-1,10],[1,-2,-2],[2,1,3]]

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If A=[[-4,4,4],[-7,1,3],[5,-3,-1]], B=[[1,-1,1],[1,-2,-2],[2,1,3]] and AB = BA, then B^(-1)=kA then k is :

Find A if [[1,0,-1],[-2,-1,4],[-1,0,2]]A = [[-1,-2,2],[3,4,-3],[3,4,-1]]

Show that: [[5,-1],[6,7]][[2,1],[3,4]] ne [[2,1],[3,4]][[5,-1],[6,7]]

Show that [[5,-1],[6,7]] [[2,1],[3,4]] ne [[2,1],[3,4]] [[5,-1],[6,7]]

If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

If A=[[1,-2,3],[-4,2,5]] & B=[[1,3],[-1,0],[2,4]] then verify that (AB)'=B'A'

If A=[[1,-2,3],[-4,2,5]] , B=[[1,3],[-1,0],[2,4]] then verify that (AB)'=B'A'

The inverse of the matrix [[3, -2, -1], [-4, 1, -1], [2, 0, 1]] is a) [(1,2,3),(3,3,7),(-2,-4,-5)] b) [(1,-3,5),(7,4,6),(4,2,7)] c) [(1,2,3),(2,5,7),(-2,-4,-5)] d) [(1,-3,5),(7,4,6),(4,2,-7)]

If A=[(2,1,1),(3,-1,0),(0,2,4)], B=[(9,7,-1),(3,5,4),(2,1,6)] and C=[(2,-4,3),(1,-1,0),(9,4,5)]. Varify associative law for matrix addition.