`(2xx3)^3-:(4xx9)^2xx(27xx8)^2=6^?`

Simplify : (i) (12^4xx9^3 xx 4)/(6^3 xx 8^2 xx 27) (ii) 2^3 xx a^3 xx 5a^4

Simplify: (i) (12^4xx9^3xx4)/(6^3xx8^2xx27) (ii) (25xx5^2xxt^8)/(10^3xxt^4) (iii) (3^5xx10^5xx25)/(5^7xx6^5)

Simplify: (12^4xx9^3xx4)/(6^3xx8^2xx27) (ii) (25xx5^2xxt^8)/(10^3xxt^4) (iii) (3^5xx10^5xx25)/(5^7xx6^5)

Simplify and write in exponential form : (12^(4)xx9^(4)xx4)/(6^(3)xx8^(2)xx27)

{:("Quantity A","Quantity B"),(3^(3)xx9^(6)xx2^(4)xx4^(2),9^(3)xx3^(6)xx2^(2)xx4^(4)):}

Evaluate: (6^(4)xx9^(2)xx25^(3))/(3^(2)xx4^(2)xx15^(6))

Solve :9^(8.6)xx8^(3.9)xx72^(4.4)xx9^(3.9)xx8^(8.6)=72^(?)

Observe the following pattern (1xx2)+(2xx3)=(2xx3xx4)/3, (1xx2)+(2xx3)+(3xx4)=(3xx4xx5)/3, (1xx2)+(2xx3)+(3xx4)+(4xx5)=(4xx5xx6)/3 and find the value of \ (1xx2)+(2xx3)+(3xx4)+(4xx5)+(5xx6)