Let `x^3 - 3x^2y + x^2 + 2xy^2 – x – 2y^2 + 3y - 1 = 0` represents three sides of triangle `ABC.` If area of triangle `ABC` is `Delta`, then value of `(111Delta)` is

x + 8y - 22 = 0 , 5 x + 2y - 34 = 0 , 2x - 3y + 13 = 0 are three sides of a triangle. The area of the triangle is

x+8y-22=0, 5x+2y-34=0, 2x-3y+13=0 are the three sides of a triangle. The area of the triangle is

x+8y-22=0,5x+2y-34=0,2x-3y+13=0 are the three sides of a triangle.The area of the triangle is

2x^(2)-5xy+2y^(2)=0 represents two sides of a triangle whose centroid is (2, 3) then area of triangle is

Let the points of intersections of the lines x -y +1 = 0, x -2y + 3 = 0 and 2x -5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is _______ .

Let the points of intersections of the lines x -y +1 = 0, x -2y + 3 = 0 and 2x -5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is _______ .

If A(x_1,y_1),B(x_2,y_2),C(x_3,y_3) are the vertices of the triangle then find area of triangle

The equation (x+y=6)(xy-3x-y+3=0) represents the sides of a triangle then the equation of the circumcircle of the triangle is

If y-3=0,x-3y+9=0 and 3x-2y+1=0x+y-3=0,x-3y+9=0 and 3x-2y+1=0 are sides of triangle then area of triangle.