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8.(sqrt(5)-2)^(2)=?-sqrt(80)...

8.`(sqrt(5)-2)^(2)=?-sqrt(80)`

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What will come in place of question mark(?) in the following questions? (sqrt5-2)^2=?-sqrt(80)

The following are the steps involved in finding the value of x-y from (sqrt(8)-sqrt(5))/(sqrt(8)+sqrt(5))=x-ysqrt(40) . Arrange them in sequential order. (A) (13-2sqrt(40))/(8-5)=x-ysqrt(40) (B) ((sqrt(8))^(2)+(sqrt(5))^(2)-2(sqrt(8))(sqrt(5)))/((sqrt(8))^(2)-(sqrt(5))^(2))=x-ysqrt(40) (C) x-y=(11)/(3) (D) x=(13)/(3) and y=(2)/(3) (E) ((sqrt(8)-sqrt(5))(sqrt(8)-sqrt(5)))/((sqrt(8)+sqrt(5))(sqrt(8)-sqrt(5)))=x-ysqrt(40)

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If sqrt(5)=2.236 and sqrt(10)=3.162 , then the value of (15)/(sqrt(10)+sqrt(20)+sqrt(40)-sqrt(5)-sqrt(80)) is

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(iii) ((sqrt(2))/(5))^(8)-:((sqrt(2))/(5))^(1/3)

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Solve (sqrt(5)-1)/(sinx)+(sqrt(10+2sqrt(5)))/(cosx)=8,x in (0,pi/2)