The first term of an A.P. is 'a' and sum of first p terms is zero. Show that the sum of next q terms will be `(a(p+q)q)/(1-p).`

The first term of an A.P.is a and the sum of first p terms is zero,show tht the sum of its next q terms is (a(p+q)q)/(p-1)

If the sum of p terms of an A.P. is q and the sum of q terms is p , then the sum of the p+q terms will be

7^(th) term of an A.P. is 40. Then, the sum of first 13 terms is

If the sum of p terms of an A.P.is q and the sum of q terms is p,then the sum of p+q terms will be

The first term of an A.P. is 100 and the sum of whos f first 6 terms is 5 xx the sum of the next 6 terms,then the c.d. is

In an AP of which 'a' is the Ist term, if the sum of the Ist p terms is equal to zero, show that the sum of the next q terms is -((aq(p + q))/(p - 1))

If the sum of P terms of an A.P. is q and the sum of q terms is p , then the sum of p+q terms will be (a) 0 (b) p-q (c) p+q (d) (p+q)

If the first term of an A.P. is 3 and the sum of its first 25 terms is equal to the sum of its next 15 terms, then the common difference of this A.P. is: