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Let Sn denote the sum of the cubes of th...

Let `S_n` denote the sum of the cubes of the first `n` natural numbers and `s_n` denote the sum of the first `n` natural numbers. Then `sum_(r=1)^n S_r/s_r` is equal to

A

`(n(n+1)(n+2))/6`

B

`(n(n+1))/2`

C

`(n^2 + 3n+2)/6`

D

`(n^2 + 3n+ 2) /3`

Text Solution

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The correct Answer is:
A
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