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If an>1 for all n in N then log(a2) a1+l...

If `a_n>1` for all `n in N` then `log_(a_2) a_1+log_(a_3) a_2+.....log_(a_1)a_n` has the minimum value of

A

1

B

2

C

0

D

3

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The correct Answer is:
A
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