Let f(n) = [1/2 + n/100] where [x] denot...

Let `f(n) = [1/2 + n/100]` where `[x]` denote the integral part of `x.` Then the value of `sum_(n=1)^100 f(n)` is

A

50

B

51

C

1

D

52

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

Let f(n) = [1/4 + n/1000] , where [x] denote the integral part of x. Then the value of sum_(n=1)^(1000) f(n) is

Let f(n) = [(1)/(2) + (n)/(100)] where [n] denotes the integral part of n. Then the value of sum_(n=1)^(100) f(n) is

Let f(n)=[(1)/(2)+(n)/(100)] where I 1 denotes the greatest integer function,then the value of sum_(n=1)^(151)f(n) is

If f:(0,pi)rarr R and is given by f(x)=sum_(k=1)^(n)[1+sin((kx)/(n))] where [] denotes the integral part of x, then the range of f(x) is

where f (n) = [(1)/(3) + (3n)/(100)] n, where [ n] denotes the greatest integer less than or equal to n. Then sum_(n=1)^(56)int (n) is equal to :

The value of sum_(n=1)^100 int_(n-1)^n e^(x-[x])dx =