sum(r=1)^n (r^2 - r-1)/((r+1)!) is equal...

`sum_(r=1)^n (r^2 - r-1)/((r+1)!)` is equal to :

A

`n/((n+1)!)`

B

`(-1)/((n+1)(n-1)!)`

C

`n/((n+1)!)-1`

D

`n/((n-1)!)+1`

Verified by Experts

The correct Answer is:

B

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